Question

How do you find the limit of `(4x² -2x^15 +17)/(3x^6 - 7x^3 + 216)` as x approaches infinity?

Answer 1

`-oo`

Explanation:

Divide the numerator and denominator by `x^6`,the given expression would become

`((4/x^4 -2x^9 +17/x^6))/(3-7/x^3 +216/x^6)`

Now apply the limit `x->oo`, it would become `-oo/3`= `-oo`