What is the derivative of #y=arcsin(3x+5)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Konstantinos Michailidis Sep 13, 2015 It is #dy/dx=(3/sqrt(1-(3x+5^2)))# Explanation: The derivative of #y=arcsing(x)# is #dy/dx=(g'(x))/sqrt(1-g^2(x))# where g(x)=3x+5 hence we have that #dy/dx=(3/sqrt(1-(3x+5^2)))# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 2538 views around the world You can reuse this answer Creative Commons License