Question

Milton and Bonnie are hiking. Milton averages 4 mph, and Bonnie averages 3 mph. If they start out together in the morning, but Milton gets to camp 2 hours and 30 minutes ahead of Bonnie, then how many miles did they hike that day?

Answer 1

I found `30m`

Explanation:

Considering:
`v=d/t` where `v` is velocity, `d` distance and `t` time:
Milton does: `4=d/t`
Bonnie does: `3=d/(t+2.5)`
Where 2h and 30 min correspond to `2.5h`.
You get:
`4t=3(t+2.5)`
`4t=3t+7.5`
`t=7.5h`
Use it into the first equation:
`d=4t=4*7.5=30m`