How do you find the integral of int lnx dx ∫lnxdx from 0 to 4? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer Dharma R. Sep 16, 2015 8ln2-48ln2−4 Explanation: int_0^4∫40 lnxdxlnxdx by applying byparts lnxlnxint_0^4∫40dxdx-int_0^4∫401/x1xxdxxdx(apply lmints for lnx also) =(ln4*4-ln0*0)ln4⋅4−ln0⋅0)-(4-04−0) = 8ln2-48ln2−4 Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of ln(7x)ln(7x)? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of x^2-6x+5x2−6x+5 from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral 1/(sqrt(49-x^2))1√49−x2 from 0 to 7sqrt(3/2)7√32? How do you integrate f(x)=intsin(e^t)dtf(x)=∫sin(et)dt between 4 to x^2x2? How do you determine the indefinite integrals? How do you integrate x^2sqrt(x^(4)+5)x2√x4+5? See all questions in Definite and indefinite integrals Impact of this question 1565 views around the world You can reuse this answer Creative Commons License