What is the derivative of y=xcosx+sinx? Calculus Differentiating Trigonometric Functions Differentiating sin(x) from First Principles 1 Answer Dharma R. Sep 16, 2015 2cosx−x⋅sinx Explanation: derrivtive of xcosx can be fund bu uv rule and is cosx−x⋅sinx and sinx derivative is cos x adding both answers lead to 2cosx−x⋅sinx Answer link Related questions How do you differentiate f(x)=sin(x) from first principles? What is the derivative of y=3sin(x)−sin(3x)? How do you find dy/dx if x+tan(xy)=0? How do you find the derivative of the function y=cos(1−e2x1+e2x)? How do you differentiate f(x)=2secx+(2ex)(tanx)? How do you find the derivate for y=πsinx−4cosx? How do you find the derivative of f(t)=t2sint? What is the derivative of sin2(lnx)? How do you compute the 200th derivative of f(x)=sin(2x)? How do you find the derivative of sin(x2+1)? See all questions in Differentiating sin(x) from First Principles Impact of this question 14542 views around the world You can reuse this answer Creative Commons License