Question #68c84

1 Answer
Sep 17, 2015

sqrtx/2-(2x^10)/5+C

Explanation:

int(sqrtx-4x^10)/x dx=intsqrtx/xdx-int(4x^10)/x dx=

=intx^(-1/2)dx-4intx^9dx=1/2x^(1/2)-4 x^10/10+C=

=sqrtx/2-(2x^10)/5+C