Question

How do you evaluate `int x^2 + x + 4dx` for [0, 2]?

Answer 1

`38/3`

Explanation:

#int_0^2x^2+x+4dx=int_0^2x^2dx+int_0^2xdx+int_0^24dx =[x^3/3]_0^2+[x^2/2]_0^2+4[x]_0^2=8/3+4/2+8-0=38/3#