Question

Given that `2^(x-3)/8^(2y-3)` = `16^(x-y)` , show that `3x + 2y = 6` ?

Answer 1

Refer to explanation

Explanation:

We have that

#2^(x-3)/8^(2y-3)=16^(x-y)=>2^(x-3)=8^(2y-3)*16^(x-y)=> 2^(x-3)=2^(3*(2y-3))*2^(4*(x-y))=> 2^(x-3)=2^(6y-9)*2^(4x-4y)=>2^(x-3)=2^(6y-9+4x-4y)=> x-3=6y-9+4x-4y=>9-3=4x-x+6y-4y=> 3x+2y=6#