What is the limit of #(x-1)(x-2)(x-3)(x-4)(x-5)/(5x-1)^5# as x goes to infinity?

1 Answer
Sep 27, 2015

You can separate this into multiple limits using their multiplicative properties.

#= lim_(x->oo) (x-1)/(5x - 1) * lim_(x->oo) (x-2)/(5x - 1) * lim_(x->oo) (x-3)/(5x - 1) * lim_(x->oo) (x-4)/(5x - 1) * lim_(x->oo) (x-5)/(5x - 1)#

Then, we can "simplify" this down using the fact that as #x# becomes really large, the evaluation #(x)/(5x) ~~ 1/5# on each limit becomes more and more accurate (with #x# >> #1#, the #1# becomes insignificant at large #x#).

Since there are five of these limits, you get

#(1/5) * (1/5) * (1/5) * (1/5) * (1/5)#

#= 1/(5^5)#, or #color(blue)(1/(3125))#.