Question #d4ec7

1 Answer
Konstantinos Michailidis · Dr. Hayek
Sep 27, 2015

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Explanation:

The calculation uses this equation:

#q = (mass) (Δt) (Cp)#
This summarizes the information needed:

#Δt = 25.7-12.5=13.2 C#
#mass = 25.0 g#
#Cp = 4.184 J g¯1 °C¯1#

Substituting, we have:

#q = (25.0 g) (13.2 °C) (4.184 J g¯1 °C¯1) q = 1380.72J#

And #1 joule# is equal to #0.238902957619# calories.

Hence 1380.72J are about #329.86C#

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