Question

How do you multiply `root3a (root3(a^2) + root3(81a^2))`?

Answer 1

I found: `a(1+3root3(3))`

Explanation:

We can multiply first:
`root3(a)*root3(a^2)+root3(a)*root3(81a^2)=` and rearrange:
`=root3(a*a^2)+root3(a*81a^2)=`
`=root3(a^3)+root3(81a^3)=` taking cube roots:
`=a+aroot3(81)=a+aroot3(27*3)==a+3aroot3(3)=`
`=a(1+3root3(3))`