How do you solve #4x-30> -3x+12#?

2 Answers

Refer to explanation

Explanation:

What you got is called inequality .You need to find the values of variable x that make the inequality true. Hence

#4x-30 > -3x+12#
Move -30 to other side and change sign.
#4x>30-3x+12#
Move -3x to other side and change sign as well
#4x+3x>30+12#
Now add in both sides
#7x>42#
Divide by 7 both sides
#(7x)/7>(42)/7#
Simplify
#x>6#

Hence the values of x that satisfy the inequality belong to interval
#(6,+oo)#

Oct 3, 2015

The answer is #x>6# .

Explanation:

#4x-30> -3x+12#

Solve as if this were an equation.

Add #30# to both sides of the inequality.

#4x> -3x+12+30=#

#4x> -3x+42#

Add #3x# to both sides of the inequality.

#4x+3x>42=#

#7x>42#

Divide both sides by #7#.

#x>42/7=#

#x>6#