What is the inverse function of #y=5^x+1#?

1 Answer
Oct 4, 2015

#f(y) = log_5(y-1)#
#f^(-1)(x) = log_5(y-1)#
#x = log_5(y-1)#

Explanation:

Isolate the terms with an #x#

#y = 5^x + 1#
#y - 1 = 5^x#

Take the log of base 5 of both sides

#log_5(y-1) = x#

Other common notations will have you replace #x# for #f(y)# or replace #x# for #f^(-1)(x)# and #y# for #x#, like this:

#f(y) = log_5(y-1)#
#f^(-1)(x) = log_5(y-1)#
#x = log_5(y-1)#

I personally care more for the first and the third, but they all have their strengths. The first cleary indicates this is a function in terms of #y#, the second that this is an inverse function to find #x# and the third explicits the relation between #x# and #y#.

Your teacher will probably want you to put down the second or the third though, so try to remember that step.