What is the inverse of #f(x) = (4x-1)/(2x+3#?
1 Answer
Oct 4, 2015
#f^(-1)(y) = (1+3y)/(4-2y)#
Explanation:
Let
Add
#7/(2x+3) = 2 - y#
Multiply both sides by
#7/(2-y) = 2x + 3#
Subtract
#7/(2-y) - 3 = 2x#
Divide both sides by
#x = (7/(2-y)-3)/2#
#= (7 - 3(2-y))/(2(2-y))#
#= (1+3y)/(4-2y)#
So:
#f^(-1)(y) = (1+3y)/(4-2y)#