Question

Question #8c731

Answer 1

`m=0.63g`

Explanation:

The molarity is calculated by:

`C_M=n/(V)`

where `n` is the number of mole of `H_2C_2O_4*2H_2O` and `V` is the volume of the solution.

`=>n=C_MxxV=0.05(mol)/(cancel(L))xx0.1cancel(L)=5xx10^(-3)mol`

The mass (`m`) of `H_2C_2O_4*2H_2O` can be then calculated by:

`m=nxxMM=5xx10^(-3)cancel(mol)xx126g/(cancel(mol))=0.63g`

`MM` is the molar mass of `H_2C_2O_4*2H_2O`