How do you add #sqrt2+sqrt2#? Algebra Radicals and Geometry Connections Addition and Subtraction of Radicals 1 Answer MeneerNask Oct 6, 2015 Think of it as #1*sqrt2+1*sqrt2# Explanation: Then it's obvious that the answer should be #2sqrt2# Answer link Related questions How do you add and subtract radicals? How is a radical considered a "like term"? How do you simplify #4\sqrt{3}+2\sqrt{12}#? How do you add #3""^3sqrt(2)+5""^3sqrt(16)#? How do you subtract #\sqrt{8x^3}-4x\sqrt{98x}#? How do you combine the radical #\sqrt{6}-\sqrt{27}+2\sqrt{54}+3\sqrt{48}#? How do you simplify #""^3sqrt{\frac{16x^5}{135y^4}}#? What is #sqrt(50)-sqrt(18)#? How do you add #3sqrt2+4sqrt2#? What is the square root of 50 + the square root of 8? See all questions in Addition and Subtraction of Radicals Impact of this question 19930 views around the world You can reuse this answer Creative Commons License