How do you evaluate #log_(1/2) (9/4)#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer bp Oct 6, 2015 # log(9/4) / log (1/2)# Explanation: Let #x= log_(1/2) (9/4)# Then it is #(1/2)^x = 9/4# Taking log on both sides x=# log(9/4) / log (1/2)#. This can be evaluated in decimals if required. Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 1492 views around the world You can reuse this answer Creative Commons License