Question

How do you find the derivative of `cos(2x)^4`?

Answer 1

I found: `=-64x^3sin(2x)^4=-64x^3sin(16x^4)`

Explanation:

I would try using the Chain Rule, deriving the `cos` as it is (red) and then multiply by the derivative of the argument (blue) to get:
`f'(x)=color(red)(-sin(2x)^4)*color(blue)(4(2x)^3*2)=-64x^3sin(2x)^4`