How do you identify stereocenters on a complex molecule?

1 Answer
Oct 8, 2015

Perhaps you can analogize off of the answer I will put here. This is a rather comprehensive molecule I got on an exam for identifying stereocenters:

http://1.bp.blogspot.com/
Morphine

#~95%# of the time, stereocenters are in #sp^3# carbons. The stereocenters I identify are:

  • Carbon-5, connected to an #1^o# alkoxide group, a tert-butyl group, a proton, and a #2^o# alcohol group. The priorities from high to low are:

    #1^o# alkoxide, #2^o# alcohol, tert-butyl, proton

Since the proton is in the front, and you go counterclockwise to follow these priorities, you get the reverse of S, which is R.

  • Carbon-6, connected to a #2^o# alkoxide group, a vinyl or alkenyl group, a proton, and a hydroxyl group. The priorities from high to low are:

    hydroxyl, #2^o# alkoxide, vinyl (counted similar to isopropyl), proton

Since the proton is in the front, and you go clockwise to follow these priorities, you get the reverse of R, which is S.

  • Carbon-9, connected to a #2^o# amine group, a proton, a methylene group (#CH_2#), and an isopropyl group. The priorities from high to low are:

    #2^o# amine, isopropyl, methylene, proton

Since the proton is in the back and you go clockwise to follow the priorities, this is R.

  • Carbon-13 (the one that branches upwards), connected to a benzene ring, a #2^o# alkoxide group, an isopropyl group, and a #1^o# alkyl group. The priorities from high to low are:

    #2^o# alkoxide, benzene ring (counted similar to tert-butyl), isopropyl, #1^o# alkyl

Since the #1^o# alkyl is upwards and you go clockwise to follow the priorities, this is the reverse of R, which is S.

  • Carbon-14, connected to a proton, a tert-butyl group, a vinyl or alkenyl group, and a #2^o# amine group. The priorities from high to low are:

    #2^o# amine, tert-butyl, vinyl (counted similar to isopropyl), proton

Since the proton is in the front and you go counterclockwise to follow the priorities, this is the reverse of S, which is R.