The current world-record motorcycle jump is 77.0m,set by Jason Renie.Assume that he left the take-off ramp at 12.0° to the horizontal and that the takeoff and landing heights are the same.Neglecting air drag, how do I find his takeoff speed?

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Answer 1 · 2015-10-12T18:49:07

You can do it like this:

The time - independent expression for the range given a flat surface is:

#d=(v^2sin2theta)/(g)#

#v^2=(d.g)/(sin2theta)#

#v^2=(77.0xx9.8)/(sin24)#

#v^2=1855.4#

#v=43.07"m/s"#