Question #9c320

1 Answer

(a) 10 bulbs, assuming AC mains voltage = 120V.

Explanation:

The bulbs must be connected in series, so the mains voltage will be equally divided by the bulbs. Then:

(a) Nr. of bulbs = 120/12 = 10 bulbs.

(b) Total power = 1 W x 10 bulbs = 10 W.

(c) Voltage drop across each bulb = 120/10 = 12V

(d) As they are in series, the current is the same.

I = P/V = 10/120 = 0,08333 A

Resistance of each bulb = V^2/P = 12^2/1 = 144 ohm.