Petra is 4 times as old as Philippa. In 8 years time she will be 5 times as old as Philippa. How old are Philippa and Petra?

2 Answers
Oct 17, 2015

The question as given has no positive solutions.

If the #4# and #5# were the other way round then Petra's current age is #120# and Philippa's #24#.

Explanation:

The question as given has no positive solutions.

Let Petra's current age be #x# and Philippa's #y#.

We are given:

#x = 4y#

#x+8 = 5(y + 8) = 5y + 40#

Subtract the first of these equations from the second to get:

#8 = x+8 - x = 5y+40 - 4y = y + 40#

Subtract #40# from both sides to get:

#y = -32#

Then

#x = 4y = 4(-32) = -128#

So Petra is #-128# and Philippa is #-32#

Alternative problem

Suppose the #4# times and #5# times were supposed to be the other way round.

Then we are given:

#x = 5y#

#x + 8 = 4(y+8) = 4y + 32#

Subtract the second equation from the first to get:

#-8 = x - (x + 8) = 5y - (4y + 32) = y - 32#

Add #32# to both ends to get:

#y = -8 + 32 = 24#

Then

#x = 5y = 5*24 = 120#

So Petra is #120# and Philippa is #24#

Oct 17, 2015

Petra = -32, Philippa = 94
Given that initial condition year is #t_0#, Petra had not been born. She would be in 32 years that is, #t_32#. Consequently Petra's age is negative.

Explanation:

I gave the wrong answer originally. Submission deleted!
Hopefully I will not get interrupted this time!!! Wrong, 4th attempt!

Let current time be #t_0#
Let time in 8 years be #t_8#
Let Petra be #"Pe"#
Let Philippa be #"Ph"#

At #t_o -> "Pe" = 4"Ph"#
Then #"Pe - 4"Ph" = 0#.................. ( 1 )

At #t_8 -> "Pe" + 8 = 5("Ph" + 8)#
Then #"Pe" -5"Ph" = 40 - 8 = 32#....... ( 2 )

Subtract ( 1 ) from ( 2 ) giving:

#-"Ph" = 32#
So #"Ph" = -32# .................... ( 3 )

( at first this looks as though it is not possible. However if you view negative age as to be born in the future then it works. So -32 means that #"Ph is to born at " t_32#
If at #t_0 " Pe"# is four times older then, stepwise we have from #"Ph's"# age:

(-32), 32, 32, 32

So #"Pe's"# age at #t_0# is #32 + 32 + 32= 94# because #Ph's# age is 32 years the other side of 0 giving a total of #4 times 32 = 128# years difference. ( #94 - (-32)) = 128#