How do you find the volume of the region enclosed by the curves #y=2x#, #y=x#, and #y=4# is revolved about the y-axis?

1 Answer
Oct 21, 2015

Volume# = 16pi#

Explanation:

The region described is the difference between two inverted cones as can be seen from the diagram below:
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The volume of the bounded region is the difference between the volume of the external cone and the internal cone.

The general formula for the volume of a cone is
#color(white)("XXX")V= (pir^2h)/3#

So the required region has a volume of
#color(white)("XXX")(pi*4^2*4)/3 - (pi*2^2*4)/3#

#color(white)("XXX")=(4pi)/3 * (16-4)#

#color(white)("XXX")=16pi#