Question

What does `((1+i)*(6-2i))/(4i)` equal?

Answer 1

`1-2i`

Explanation:

Given equation =`((1+i)(6-2i))/4i`

Expand the numerator

= `(6-2i+6i-2i^2)/(4i)`
= `(6+4i-2(-1))/(4i)`
= `(6+4i+2)/(4i)`
= `(8+4i)/(4i)`
Take 4 as common in numerator
= `(4(2+i))/(4i)`
=`(2+i)/(i)`
multiply numerator and denominator with `i`
= `(2i+i^2)/(i^2)`
= `(2i-1)/(-1)`
= `1-2i`