How do you evaluate #log sqrt 0.0001#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer GiĆ³ Oct 22, 2015 I found #-2# but I considered base #10# for your log. Explanation: I assume a log in base #10# so you have: #log_(10)(sqrt(0.0001))=log_(10)(1/10000)^(1/2)=1/2[log_(10)(1)-log_(10)(10000)]=1/2[0-4]=-2# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 2137 views around the world You can reuse this answer Creative Commons License