What are the asymptotes of: #f(x)= (3e^(x))/(2-2e^(x))#?

1 Answer
Oct 22, 2015

See explanation: Only part solution given. Left some thinking for you to do!

Explanation:

Tony B

Given that #x# is positive

If it gets bigger and bigger then the single left hand 2 in #2-2e^x# becomes of no consequence in its effect. So you end up with the equivalent of just #-3/2 times (e^x)/(e^x) = -3/2 #

If it tends to #0^+# then #e^x# tends to 1 so we end up with
the denominator being negative and getting smaller and smaller. Consequently when divided into the denominator the result is an ever increasing negative y value but on the positive side of the x-axis.

Using the graph and the approach I have demonstrated you should be able to determine the behaviour if #x# is negative.

No you try it with #x# being negative!!!!