How do you find the slope of the tangent line to the graph of the given function # y=x^2#; at (2,3)?
1 Answer
Oct 23, 2015
here,
let f(x) =y =
f'(x) will give you the slope of tangent
So ,
f'(x) =
=2x
So 2x is the slope of the tangent.
TO find the slope of tangent at the point where x=2,
we have,
Slope(m) = 2*2 = 4
So the equation of tangent with slope 4 and passing through (2,3) is given by;
(y-y1)=m(x-x1)
(y-3) =4(x-2)
y-3 = 4x - 8
So,
y= 4x-5 is the equation of the tangent of the curve y=