How do you use the double angle or half angle formulas to simplify #5-10sin^2x#? Trigonometry Trigonometric Identities and Equations Double Angle Identities 1 Answer Alan P. Oct 23, 2015 #5-10sin^2(x) = 5*cos(2x)# Explanation: By Double Angle Formula #color(white)("XXX")cos(2x) = 1-2sin^2(x)# #rArrcolor(white)("XXX")5*cos(2x) = 5-10sin^2(x)# Answer link Related questions What are Double Angle Identities? How do you use a double angle identity to find the exact value of each expression? How do you use a double-angle identity to find the exact value of sin 120°? How do you use double angle identities to solve equations? How do you find all solutions for #sin 2x = cos x# for the interval #[0,2pi]#? How do you find all solutions for #4sinthetacostheta=sqrt(3)# for the interval #[0,2pi]#? How do you simplify #cosx(2sinx + cosx)-sin^2x#? If #tan x = 0.3#, then how do you find tan 2x? If #sin x= 5/3#, what is the sin 2x equal to? How do you prove #cos2A = 2cos^2 A - 1#? See all questions in Double Angle Identities Impact of this question 1927 views around the world You can reuse this answer Creative Commons License