Question

Question #60472

Answer 1

`1s^2` `2s^2` `2p^6` `3s^2`

Explanation:

To write an electronic configuration, you first need to know the atomic number of the element. For nitrogen, atomic number is 7.

Therefore, the ground state electron configuration of nitrogen is

`1s^2` `2s^2` `2p^3` = 7 electrons

But the question is the electronic configuration of `N^"5-"`. This means that this nitrogen has `color(red)("5 excess electron from its ground state")` . So from the ground state 7 electrons, the number of electrons now is 12 electrons .

Therefore, the new electronic configuration state should be

`1s^2` `2s^2` `2p^6` `3s^2`