Question

What is the limit of `(8-(7y^2))/((2y^2)+9y)` as x goes to infinity?

Answer 1

AS `y` goes greater and greater, `y^2` goes greater at a very much faster rate.

Explanation:

So further on, the `8` above the bar and the `9y` make less and less of a difference, and the function will get nearer and nearer to
`(-7cancel(y^2))/(2cancel(y^2))=-3 1/2`

Or, in "the language":

`lim_(y->oo) (8-7y^2)/(2y^2+9y) =-3 1/2`