What value(s) of k would make #16x^2 -2/3kx+9# a perfect square trinomial?

1 Answer
Nov 1, 2015

We can say that a trinomial is a perfect square if it is in the form

#a^2x^2 + 2abxy + b^2y^2#

In the question, we want #16x^2 -2/3kx + 9# to be a perfect square trinomial

This means we can assume the following

#a^2 = 16#
#=> a = +-4#

#b^2 = 9#
#=> b = +- 3#

Since the coefficient of the second term is negative, either #a# or #b# should be negative.

Let's assume that #b# is negative.

#=> a = 4#
#=> b = -3#

#2ab = -2/3k#

#=> 2(4)(-3) = -2/3k#

#=> 4(-1 * 3) = -1/3k#

#=> 4*3 = 1/3k#

#=> 4*3*3 = k#

#=> 36 = k#

I will not show it anymore, but if we assume that #a# is negative, we should arrive at the same answer