What is #int (lnsqrt(3x+2))^2dx#?
1 Answer
Nov 2, 2015
Here is some help to get you started.
Explanation:
Let's look at the integrand for a bit:
First note that
and
Then the question will be how to find
Details
# = 1/4 int (ln(3x+2))^2 dx#
With
# = 1/12 int (lnt)^2 dt#
Now try substitution, try parts, try anything else you think of.
Hint
Recall that we can integrate