Question

What is the specific heat of a substance that absorbs `2.5*10^3` joules of heat when a sample of `1 * 10^4` g of the substance increases in temperature from 10°C to 80°C?

Answer 1

`s=3.57xx10^(-3)J/(g*""^@C)`

Explanation:

The amount of heat absorbed by the system could be calculated by:

`q=sxxmxxDeltaT`

where, `color(blue)(s)` is the specific heat capacity
`color(blue)(m)` is the mass of the object
`color(blue)(DeltaT)=T_f-T_i` is the change on temperature. `DeltaT=80 - 10 = 70^@C`

The specific heat capacity is then: `s=q/(mxxDeltaT)=(2.5xx10^3)/(1xx10^4xx70)=3.57xx10^(-3)J/(g*""^@C)`

Here is a video that fully explains this concept:
Thermochemistry | Enthalpy and Calorimetry.