Question #15c3e Calculus Graphing with the First Derivative Classifying Critical Points and Extreme Values for a Function 1 Answer BeeFree Nov 8, 2015 Find values of x's where #f'(x)=0# Explanation: #f'(x) = cos(theta)-2cos(theta)sin(theta)=cos(theta)[1-2sin(theta)]=0# #cos(theta)=0# where #theta=(pi/2 or (3pi)/2) +-2pi# #[1-2sin(theta)]=0# where #theta=(pi/6 or (5pi)/6) +-2pi# hope that helped Answer link Related questions How do you find and classify the critical points of #f(x)=x^3#? How do you find the critical points of a rational function? How do you know how many critical points a function has? How many critical points can a cubic function have? How many critical points can a function have? How many critical points can a quadratic polynomial function have? What is the first step to finding the critical points of a function? How do you find the absolute extreme values of a function on an interval? How do you find the extreme values of the function and where they occur? What is the extreme value of a quadratic function? See all questions in Classifying Critical Points and Extreme Values for a Function Impact of this question 1705 views around the world You can reuse this answer Creative Commons License