What is the vertex of the function #p(x) = (x-5)^2 + 4#?

1 Answer
Nov 9, 2015

#(5,4)#

Explanation:

The number you subtract from #x# is the x-coordinate.
The number you add on to the outside is the y-coordinate.

The vertex form equation looks like this:
the vertex is #(h,k)#
#y=a(x-h)^2 + k#

I like to think of it like this...
The number you subtract from each variable is how far it's shifted in that direction.

We can rewrite the equation above like this to make it clearer....

#y-k=a(x-h)^2#

Now it is very clear that #k# is the y-shifter and #h# is the x-shifter.