How do you find the definite integral of $\int x^{3} d x$ $int x^3dx$ from $[0, 1]$ $[0,1]$ ?

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How do you find the definite integral of $\int x^{3} d x$ $int x^3dx$ from $[0, 1]$ $[0,1]$ ?

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Answer 1 · 2015-11-09T20:34:22

$\frac{1}{4}$ $1/4$

Explanation:

We integrate from 0 to 1 and get:

$\int_{0}^{1} x^{3} d x = (\frac{x^{4}}{4})$ $int_0^1x^3dx=(x^4/4)$ from 0 to 1
$\frac{{(1)}^{4}}{4} - \frac{{(0)}^{4}}{4} = \frac{1}{4}$ $(1)^4/4-(0)^4/4=1/4$

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How do you find the definite integral of $\int x^{3} d x$ $int x^3dx$ from $[0, 1]$ $[0,1]$ ?

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Explanation:

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How do you find the definite integral of $\int x^{3} d x$ $int x^3dx$ from $[0, 1]$ $[0,1]$ ?