Question #653bd
1 Answer
Nov 10, 2015
Explanation:
This is, at first, a tricky question. However, once you learn, this type of question is easy to do. I will divide it into steps:
- We start with
#2=[1+(0.052/1)]^t# . We will use logarithms to solve this. We'll put a 'log' on both sides to start with:#log(2) = log([1+(0.052/1)]^t)# . - We are going to use a basic log 'trick'. As we know, we can put a power as a multiplication, such that
#log(2) = log([1+(0.052/1)]^t)# turns into#log(2) = t*log([1+(0.052/1)])# . - Now, we will simply divide in order to leave '
#t# ' alone. So, we pass#log([1+(0.052/1)])# from the right side, where it is multiplying, to the left side, therefore dividing. We end up with:
#t = (log(2)) / log([1+(0.052/1)])# . - Now, we simply put those values in the calculator and... Ta ra! We get the answer.
#t = 13.67# to 2 decimal points.
Tip: If you put your operations in between Hashtags/Sharps (#) these will convert from Line Format to Math Format
Hope it Helps! :D .