Question #653bd

1 Answer
Nov 10, 2015

#t = 13.67#.

Explanation:

This is, at first, a tricky question. However, once you learn, this type of question is easy to do. I will divide it into steps:

  1. We start with #2=[1+(0.052/1)]^t#. We will use logarithms to solve this. We'll put a 'log' on both sides to start with: #log(2) = log([1+(0.052/1)]^t)#.
  2. We are going to use a basic log 'trick'. As we know, we can put a power as a multiplication, such that #log(2) = log([1+(0.052/1)]^t)# turns into #log(2) = t*log([1+(0.052/1)])#.
  3. Now, we will simply divide in order to leave '#t#' alone. So, we pass #log([1+(0.052/1)])# from the right side, where it is multiplying, to the left side, therefore dividing. We end up with:
    #t = (log(2)) / log([1+(0.052/1)])#.
  4. Now, we simply put those values in the calculator and... Ta ra! We get the answer.
    #t = 13.67# to 2 decimal points.

Tip: If you put your operations in between Hashtags/Sharps (#) these will convert from Line Format to Math Format

Hope it Helps! :D .