What is the equation of the line that passes through #(3, —3)# and a slope of 3?

1 Answer
Nov 10, 2015

Use the gradient and one point equation and rearrange into the form #y=mx+c#

Explanation:

The equation of a line can be found if the gradient or 'slope' and one point on the line is know can be found with the equation: #y-y_1 = m(x-x_1)# when you have the coordinates #(x_1,y_1)# and the gradient #m#.

Substituing in the values for your case we get: #y-(-3) = 3(x-3)#

Cleanining up the two negatives and expanding the brackets on the right hand side we get: #y+3 = 3x-9#

Now we take away 3 from both sides to get it in the form #y=mx+c#

This results in the equation and answer to your question: #y = 3x-6#