Question

How many moles of acetic acid are present in 100.0 mL of 1.0 M acetic acid?

Answer 1

Concentration = `1.0 *mol *L^-1`. Volume = `100 *mL`.

Moles of HOAc = 0.10 mol `L^-1`.

Explanation:

Concentration `=` `n/V`. So `n = C xx V`. Thus, `0.1L xx 1.0 *mol L^(-1) = 0.1•mol`.