What are the solutions to x^2 = 14x - 40?

1 Answer
Nov 13, 2015

x'=10
x''=4

Explanation:

In order to use Bhaskara's formula, the expression must be equal to zero. Therefore, change the equation to:
x^2-14x+40=0,
The apply the formula:

(-b+-sqrt(b^2-4ac))/(2a), where a is the number that multiplies the quadratic term, b is the number that multiplies x and c is the independent term.

(14+-sqrt(14^2-4*(1*40)))/(2*1)=(14+-sqrt(36))/2=(14+-6)/2=7+-3

Solving for x':
x'=7+3=10

Solving for x'':
x''=7-3=4,