Question

What are the solutions to `x^2 = 14x - 40`?

Answer 1

`x'=10`
`x''=4`

Explanation:

In order to use Bhaskara's formula, the expression must be equal to zero. Therefore, change the equation to:
`x^2-14x+40=0`,
The apply the formula:

`(-b+-sqrt(b^2-4ac))/(2a)`, where a is the number that multiplies the quadratic term, b is the number that multiplies `x` and c is the independent term.

`(14+-sqrt(14^2-4*(1*40)))/(2*1)=(14+-sqrt(36))/2=(14+-6)/2=7+-3`

Solving for x':
`x'=7+3=10`

Solving for x'':
`x''=7-3=4`,