Using the midpoint formula, if you're only given $(\frac{x_{1} + x_{2}}{2}$ $((x_1 + x_2) / 2$ , $\frac{y_{1} + y_{2}}{2})$ $(y_1 + y_2) / 2)$ , is it possible to solve for $x$ $x$ and $y$ $y$ ?

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Answer 1 · 2015-11-14T17:03:43

No.

$X = (x_{1}, x_{2})$ $X = (x_1, x_2)$

$Y = (y_{1}, y_{2})$ $Y = (y_1, y_2)$

$M = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2}) = (a, b)$ $M = ((x_1 + x_2)/2, (y_1 + y_2)/2) = (a,b)$

$f (x_{1}, x_{2}) = a$ $f(x_1, x_2) = a$

$f (y_{1}, y_{2}) = b$ $f(y_1, y_2) = b$

4 unknowns and 2 equations

Using the midpoint formula, if you're only given ((x_1 + x_2) / 2(x1+x22((x_1 + x_2) / 2, (y_1 + y_2) / 2)y1+y22)(y_1 + y_2) / 2), is it possible to solve for xxx and yyy?