Question

What is the number of H atoms in 0.183 mole `C_6H_14O`?

Answer 1

There are `1.54xx10^24"H atoms"` in `"0.183 mol C"_6"H"_14"O"`.

Explanation:

One mole of `"C"_6"H"_14"O"` contains 14 moles of hydrogen atoms. This can be written as `(14"mol H atoms")/(1"mol C"_6"H"_14"O")`.

To determine how many moles of hydrogen are contained in `"0.183 mol C"_6"H"_14"O"`, multiply `"0.183 mol C"_6"H"_13"O"` times 14 moles of H atoms per 1 mole of `"C"_6"H"_14"O"`. Then multiply times `6.022xx10^23 "atoms H"`.

`0.183cancel("mol C"_6"H"_14"O")xx(14cancel("mol H" "atoms"))/(1cancel("mol C"_6"H"_14"O"))xx(6.022xx10^23"H atoms")/(1cancel("mol H atoms"))=1.54xx10^24 "H atoms"`