Question

What is the standard form of `y=5(x-3)^2+3`?

Answer 1

Standard form `-> ax^2+bx+c`
If you meant to ask: 'What is this equation when presented in standard form'? Then you have `-> y=5x^2-6x+12`

Explanation:

The standard form is `y=ax^2+bx+c`

However, if you wish to present this equation in standard form we have:

`y= 5(x^2-6x+9) +3`
`y=5x^2-6x+12`

Answer 2

`5x^2−30x+48`

Explanation:

• Expand `(x-3)^2` in the equation:

`5(x−3)(x-3)+3`

• Distribute the 5 to the first parenthesis:

`5(x-3`
`= (5 * x)+(5*`-`3)`
`= 5x-15`

So now you have `5x−15(x-3)+3`.

• Now distribute the `5x` & `-15` to the next parenthesis:

`5x−15(x-3)`
`= (5x*x)+(5x*`-`3)+(`-`15*x)+(`-`15*`-`3)`
`=5x^2-15x-15x+45`
`=5x^2-30x+45`

So now you have `5x^2-30x+45+3`.

• Finally, add the constant `(`+`3)`:

`45+3 = 48`

• Final Answer:

`5x^2-30x+48`