Question

Question #466e7

Answer 1

Here's what I got.

Explanation:

As you know, frequency and wavelength have an inverse relationship described by the equation

`color(blue)(c = lamda * nu)" "`, where

`c` - the speed of light in vacuum, approximately equal to `3 * 10^(8)"m s"^(-1)`
`lamda` - the wavelength of the wave
`nu` - the frequency of the wave

Now, a tarehertz is equivalent to `10^12` hertz, which in turn is equivalent to

`"1 Hz" = "s"^(-1)`

This means that your frequency of `"600 THz"` will be equal to

`"600 THz" = 600 * 10^(12)"s"^(-1)`

Plug in your values in the above equation and solve for `lamda`, the wavelength of the wave

`c = lamda * nu implies lamda = c/(nu)`

`lamda = (3 * 10^(8)"m" color(red)(cancel(color(black)("s"^(-1)))))/(600 * 10^12color(red)(cancel(color(black)("s"^(-1))))) = 0.005 * 10^(-4)"m" = 500 * 10^(-9)"m" = "500 nm"`

To determine the color of the light wave, take a look at the electromagnetic spectrum

A wavelength of `"500 nm"` places you in the visible light range. Your light wave is somewhere between blue, which ranges fro m`450` to `"495 nm"`, and green, which ranges from `495` to `"50 nm"`.

More specifically, your light wave will have a cyan color.