A bottle of $K M n O_{4}$ $KMnO_4$ contains 66.38 g of the compound. How many moles of $K M n O_{4}$ $KMnO_4$ does it contain?

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A bottle of $K M n O_{4}$ $KMnO_4$ contains 66.38 g of the compound. How many moles of $K M n O_{4}$ $KMnO_4$ does it contain?

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Answer 1 · 2015-11-18T19:27:33

$0.42$ $0.42$ g/mol

Explanation:

The number of moles in a compound is given by the formula:
moles $= \frac{m a s s}{m o l . m a s s}$ $=(mass)/(mol. mass)$
Molar mass of $K M n O_{4} = 158.034$ $KMnO_4=158.034$
Given mass of $K M n O_{4} = 66.38 g$ $KMnO_4= 66.38g$

moles of $K M n O_{4} =$ $KMnO_4 =$ $\frac{66.38}{158.034} = 0.42$ $66.38/158.034=0.42$ g/mol

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A bottle of $K M n O_{4}$ $KMnO_4$ contains 66.38 g of the compound. How many moles of $K M n O_{4}$ $KMnO_4$ does it contain?

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A bottle of KMnO4KMnO_4 contains 66.38 g of the compound. How many moles of KMnO4KMnO_4 does it contain?

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A bottle of $K M n O_{4}$ $KMnO_4$ contains 66.38 g of the compound. How many moles of $K M n O_{4}$ $KMnO_4$ does it contain?