What is the standard form of #y= (-2x-1/5)(3/7x-1) #? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Nghi N. Nov 19, 2015 Find standard form Explanation: #y = -(2x + 1/5)((3x)/7 - 1)# = -35(10x + 1)(3x - 7) # #y = -35(30x^2 - 70x + 3x - 7) = -35(30x^2 - 67x - 7)# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1139 views around the world You can reuse this answer Creative Commons License