Question

If 2% of the batteries manufactured by a company are defective, what is the probability that in a case of 144 batteries, there are 3 defective ones?

Answer 1

This is Binomial with p = 0.02 and n =144

Explanation:

`P(X=3) =((144!)/(3!xx141!))(0.02)^3(1-0.02)^141~~0.22584`

hope that helped