Question

A boy finds himself at the bottom of a hole 1.25 meters deep. If the boy is to jump out of the hole, with what minimum velocity must he launch himself?

Answer 1

`4.95"m/s"`

Explanation:

`v^2=u^2+2as`

In this case we can set `v=0` which means he will just reach the surface:

`:.0=u^2-2xxgxx1.25`

`u^2=2xx9.9xx1.25`

`u=4.95"m/s"`