Question

A squirrel sitting on the ground starts to run with an acceleration of `5.1` `m``/``s^2`. How fast is the squirrel going after `.25` seconds?

Answer 1

`1.27"m/s"`

Explanation:

Use `v=u+at`

Since `u`, the initial velocity, is zero we can write:

`v=0+at`

`:.v=0+5.1xx0.25=1.27"m/s"`