Question

How do you expand `ln((3x^2y^3) /22)`?

Answer 1

`=ln(3/22)+2ln(x)+3ln(y)`

Explanation:

`{(ln((ab)/c)=ln(a)+ln(b)-ln(c)),(ln(a^b)=bln(a)):}`

`ln((3x^2y^3)/22)=ln(3)+ln(x^2)+ln(y^3)-ln(22)`

`ln(3)+2ln(x)+3ln(y)-ln(22)`

`=ln(3/22)+2ln(x)+3ln(y)`